science-notes/source/electronics/metrics.rst
2024-03-06 19:47:22 +01:00

85 lines
2.4 KiB
ReStructuredText

Metrics
---------------
Coulomb
^^^^^^^^^^
In a circuit, charges (electrons) flow.
This amount of charge is extremely huge.
The *Coulomb* unit allows to count them more easily.
Thus, :math:`1C \approx 6.241e^{18}` charges (electrons in our case).
Newton
^^^^^^^^^^^
It is a unit of force.
It is indirectly used in electronics (see Joule).
One Newton is the force required to accelerate :math:`1Kg` of mass, at a rate of
:math:`1m.s^{-1}` every seconds.
.. math::
[N]=kg.m.s^{-2}
Joule
^^^^^^^^^^
It is the unit of energy.
Its the force used to move an object when a force of one newton acts on that object in the direction of the force's motion through a distance
of one metre.
.. math::
[J]=[N] \times m=kg.m^2.s^{-2}
Watt
^^^^^^^
It is the amount of Joules per seconds spent by a system.
Ampere
^^^^^^^^
In a working circuit, electrons (Coulomb) are flowing.
They are flowing at a certain bitrate.
This is exactly what ampere measure.
.. math::
[A]=\frac{C}{s}=C.s^{-1}
Volt
^^^^^^^
To move charges in a circuit, energy is required (energy that push the charges).
This is what volts measure.
A volt is the amount of energy per Coulomb (remember Coulomb
is just a constant).
.. math::
[V]=\frac{[J]}{C}=kg.m^2.s^{-2}.C^{-1}=kg.m^2.s^{-3}.C^{-1}.s=kg.m^2.s^{-3}.[A]^{-1}
Farad
^^^^^^^^
Components can hold electrons (such as capacitor).
Farad defines the amount of Coulomb (electrons) retained by the component for each unit of voltage.
.. math::
{[F]}=\frac{C}{[V]}=\frac{C}{kg.m^2.s^{-3}.[A]^{-1}}&=\frac{C}{kg.m^2.s^{-3}.C^{-1}.s}=\frac{C}{kg.m^2.s^{-2}.C^{-1}}
&=\frac{C^2}{[J]} =\frac{C^2}{[N].m} =\frac{s^2.C^2}{kg.m}
&=\frac{s^4.[A]^2}{kg.m}=m^{-2}.kg^{-1}.s^4.[A]^2
Ohm
^^^^^^^
In circuits, components can resist to the current and thus reduces it.
Ohm defines the amount of volts required at one end of the resistor to pass one ampere into it.
.. math::
{[\Omega]}=\frac{[V]}{[A]}=\frac{kg.m^2.s^{-3}.[A]^{-1}}{[A]}=kg.m^2.s^{-3}.[A]^{-2}&=kg.m^2.s^{-3}.C^{-2}.s^{2}
&=kg.m^2.s^{-1}.C^{-2}
Henry
^^^^^^^^^^
An inductor is resisting to change in current.
When current is changing, a voltage appears at the inductor terminals.
Henry corresponds to the voltage measurable across the inductor terminals when the current is changing at a rate of one ampere per second.
.. math::
H=\frac{[V].s}{[A]}=\frac{kg.m^2.s^{-3}.[A]^{-1}}{[A]} \times s = \frac{m^2.kg}{s^2.[A]^2} = m^2.kg.s^{-2}.[A]^{-2}