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Loic Guegan 2023-10-18 22:14:14 +02:00
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commit 3f68e99707

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@ -122,7 +122,7 @@ When computing the standard deviation of :math:`X`, we have:
s^2=\frac{\sum_{i=0}^n (x_i-\overline{x})^2}{n} s^2=\frac{\sum_{i=0}^n (x_i-\overline{x})^2}{n}
In this case, the degree of freedom is :math:`n-1`. As the mean is already known, only :math:`n-1` In this case, the degree of freedom is :math:`n-1`. As the mean is already known, only :math:`n-1`
of the :math:`x_i` are allowed to vary. By knowing :math:`n-1` of the :math:`x_i`, we can deduce the last of the :math:`x_i` are allowed to vary. In fact, by knowing :math:`n-1` of the :math:`x_i`, we can deduce the last
one as follow: one as follow:
.. math:: .. math::